(2r-1)^2=3r+16

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Solution for (2r-1)^2=3r+16 equation: 



(2r-1)^2=3r+16

We move all terms to the left:

(2r-1)^2-(3r+16)=0

We get rid of parentheses

(2r-1)^2-3r-16=0

We add all the numbers together, and all the variables

-3r+(2r-1)^2-16=0

We move all terms containing r to the left, all other terms to the right

-3r+(2r-1)^2=16

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